- Phương trình đẳng cấp và phương trình đối xứng v...

A \(\frac{\pi }{6} + k\pi \)

B \({\rm{ }}\frac{\pi }{{12}} + \frac{{k\pi }}{2}\)

C \({\rm{ }}\frac{\pi }{3} + k\pi \)

D \({\rm{ }}\frac{\pi }{{12}} + k\pi \)

A \({\rm{ }}\frac{\pi }{4} + k\pi \;\;\left( {k \in Z} \right)\)

B \(\frac{\pi }{4} + k\pi ,\;\;{\rm{arctan}}\left( {\frac{{\rm{1}}}{{\rm{2}}}} \right) + k\pi \;\;\left( {k \in Z} \right)\)

C \( - \frac{\pi }{4} + k\pi ,\;\;{\rm{arctan}}\left( {\frac{{\rm{1}}}{{\rm{2}}}} \right) + k\pi \;\;\left( {k \in Z} \right)\)  

D \( - \frac{\pi }{4} + k2\pi ,\;\;{\rm{arctan}}\left( {\frac{{\rm{1}}}{{\rm{2}}}} \right) + k2\pi \)

A \(\left[ \begin{array}{l}x = k\frac{\pi }{2}\\x = k\frac{\pi }{4}\end{array} \right.\,\,\left( {k \in \mathbb{Z}} \right)\)

B \(\left[ \begin{array}{l}x = k\pi \\x = k\frac{\pi }{2}\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\)

C \(\left[ \begin{array}{l}x = \frac{\pi }{2} + k\pi \\x = k\pi \end{array} \right.\,\,\left( {k \in \mathbb{Z}} \right)\)

D \(\left[ \begin{array}{l}x = \frac{\pi }{2} + k2\pi \\x = k2\pi \end{array} \right.\,\,\left( {k \in \mathbb{Z}} \right)\)

A \(x =  \frac{\pi }{4} + k\pi ,\,k \in \mathbb{Z}.\)

B \(x = -\frac{\pi }{4} + k\pi ,\,k \in \mathbb{Z}.\)

C \(x =  - \frac{\pi }{4} + k2\pi ,\,k \in \mathbb{Z}.\)

D \(x =  - \frac{\pi }{4} + \frac{{k\pi }}{2},\,k \in \mathbb{Z}.\)

A \(x = k\pi \left( {k \in \mathbb{Z}} \right).\)

B \(x = k2\pi \left( {k \in \mathbb{Z}} \right).\)           

C \(x = \frac{{k\pi }}{2}\left( {k \in \mathbb{Z}} \right).\)

D \(x = \frac{{k\pi }}{4}\left( {k \in \mathbb{Z}} \right).\)

A \(\left[ \begin{array}{l}x = \frac{\pi }{4} + k2\pi \\x = \arctan \frac{1}{3} + k2\pi \end{array} \right.\left( {k \in \mathbb{Z}} \right).\)

B \(\left[ \begin{array}{l}x =  - \frac{\pi }{4} + k\pi \\x =  - \arctan \frac{1}{3} + k\pi \end{array} \right.\left( {k \in \mathbb{Z}} \right).\)

C \(\left[ \begin{array}{l}x = \frac{\pi }{4} + \frac{{k\pi }}{2}\\x = \arctan \frac{1}{3} + \frac{{k\pi }}{2}\end{array} \right.\left( {k \in \mathbb{Z}} \right).\)

D \(\left[ \begin{array}{l}x = \frac{\pi }{4} + k\pi \\x = \arctan \frac{1}{3} + k\pi \end{array} \right.\left( {k \in \mathbb{Z}} \right).\) 

A \(\left[ \begin{array}{l}x =  - \frac{\pi }{2} + k2\pi \\x = \pi  + k2\pi \,\,\,\,\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\)

B \(\left[ \begin{array}{l}x =  - \frac{\pi }{2} + k\pi \\x = \pi  + k\pi \,\,\,\,\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\)

C \(\left[ \begin{array}{l}x = \frac{\pi }{2} + k2\pi \\x =  - \pi  + k2\pi \,\,\,\,\end{array} \right.\,\,\,\left( {k \in \mathbb{Z}} \right)\)

D \(\left[ \begin{array}{l}x =  - \frac{\pi }{2} + k\pi \\x =  - \pi  + k\pi \,\,\,\,\end{array} \right.\,\,\left( {\,k \in \mathbb{Z}} \right)\)

A \(\left[ \begin{array}{l}x = \frac{\pi }{4} + k\pi \\x = k\pi \end{array} \right.\)

B \(\left[ \begin{array}{l}x = \frac{\pi }{2} + k2\pi \\x = k2\pi \end{array} \right.\)  

C \(\left[ \begin{array}{l}x = \frac{{3\pi }}{4} + k\pi \\x = k\frac{\pi }{2}\end{array} \right.\)

D \(\left[ \begin{array}{l}x = \frac{{3\pi }}{2} + k2\pi \\x = \left( {2k + 1} \right)\pi \end{array} \right.\)

A 18

B 9

C 27

D 36

A 4

B 8

C 2

D 6

A 3

B 2

C 4

D 6

A \(\frac{{7\pi }}{6}\)

B \(\frac{{3\pi }}{4}\)

C \(\frac{{5\pi }}{4}\)

D \(\pi \)

A 3040

B 15

C 20

D 25

A \(2\pi \)

B \(3\pi \)

C \(\frac{{3\pi }}{2}\)

D \(\frac{{5\pi }}{2}\)

A \(m. \ge  - \frac{1}{8}\)

B \(m. \le  - \frac{1}{8}\)

C \(m. \ge  - \frac{1}{8};m \ne 0.\)

D \(m. \ge 0\)

A 12

B 13

C 11

D 10

A 3

B 4

C 5

D 6

A \(\frac{\pi }{3}\)

B \(\frac{\pi }{2}\)

C \(\frac{\pi }{4}\)

D \(\pi \)

A 0

B 1

C 2

D 3

A 3

B 4

C 2

D 1