BTVN - Phương trình lượng giác (Tiết 3) - Có lời g...

A \(\left[ \begin{array}{l}x = \dfrac{\pi }{4} + k2\pi \\x =  - \dfrac{\pi }{4} + k2\pi \end{array} \right.\)

B \(\left[ \begin{array}{l}x = \dfrac{\pi }{4} + k\pi \\x =  - \dfrac{\pi }{4} + k\pi \end{array} \right.\)

C \(x = \dfrac{\pi }{4} + k2\pi \)

D \(x =  - \dfrac{\pi }{4} + k2\pi \)  

A

\(x =  \pm \dfrac{\pi }{4} + k\pi \)

B

\(x = \dfrac{\pi }{4} + k\pi \)

C

\(x = \dfrac{\pi }{6} + k\pi \)

D

\(\left[ \begin{array}{l}x = \dfrac{\pi }{4} + k\pi \\x = \dfrac{\pi }{6} + k\pi \end{array} \right.\)

A

\(\left[ \begin{array}{l}x = \dfrac{\pi }{3} + k2\pi \\x =  - \dfrac{{7\pi }}{3} + k2\pi \end{array} \right.\)  

B

\(\left[ \begin{array}{l}x =  - \dfrac{\pi }{3} + k4\pi \\x = \dfrac{{7\pi }}{3} + k4\pi \end{array} \right.\)

C

\(\left[ \begin{array}{l}x =  - \dfrac{\pi }{3} + k2\pi \\x = \dfrac{{7\pi }}{3} + k2\pi \end{array} \right.\)

D

\(\left[ \begin{array}{l}x = \dfrac{\pi }{3} + k4\pi \\x =  - \dfrac{{7\pi }}{3} + k4\pi \end{array} \right.\)

A \(S = \left\{ { \pm \dfrac{{2\pi }}{3} + k\pi } \right\}.\)

B \(S = \left\{ {  \dfrac{{2\pi }}{3} + k2\pi } \right\}.\)

C \(S = \left\{ { \pm \dfrac{{2\pi }}{3} + k2\pi } \right\}.\)

D \(S = \left\{ {-  \dfrac{{2\pi }}{3} + k2\pi } \right\}.\)

A \(S = \left\{ { \dfrac{\pi }{2} + k\pi } \right\}.\)

B \(S = \left\{ { \dfrac{\pi }{2} + k2\pi } \right\}.\)

C \(S = \left\{ { - \dfrac{\pi }{2} + k\pi } \right\}.\)

D \(S = \left\{ { - \dfrac{\pi }{2} + k2\pi } \right\}.\)

A \(S = \left\{ {\dfrac{\pi }{6} + k2\pi ;\dfrac{{5\pi }}{6} + k2\pi } \right\}.\)

B \(S = \left\{ {-\dfrac{\pi }{6} + k2\pi ;\dfrac{{5\pi }}{6} + k2\pi } \right\}.\)

C \(S = \left\{ {\dfrac{\pi }{6} + k2\pi ;-\dfrac{{5\pi }}{6} + k2\pi } \right\}.\)

D \(S = \left\{ {-\dfrac{\pi }{6} + k2\pi ;-\dfrac{{5\pi }}{6} + k2\pi } \right\}.\)

A \(S = \left\{ {\dfrac{\pi }{4} + k\pi ; - \dfrac{\pi }{3} + k\pi } \right\}\)

B \(S = \left\{ {\dfrac{\pi }{4} + k\pi ; \dfrac{\pi }{3} + k\pi } \right\}\)

C \(S = \left\{ {-\dfrac{\pi }{4} + k\pi ; - \dfrac{\pi }{3} + k\pi } \right\}\)

D \(S = \left\{ {-\dfrac{\pi }{4} + k\pi ; \dfrac{\pi }{3} + k\pi } \right\}\)

A \(S = \left\{ {k2\pi ,\,\,\dfrac{\pi }{4} + k\pi } \right\}\)

B \(S = \left\{ {k\pi ;\dfrac{\pi }{4} + \dfrac{{k\pi }}{2}} \right\}\)

C \(S = \left\{ {k2\pi ;\dfrac{\pi }{4} + \dfrac{{k\pi }}{2}} \right\}\)

D \(S = \left\{ {k\pi ,\,\,\dfrac{\pi }{4} + k\pi } \right\}\)

A \(S = \left\{ {-\dfrac{\pi }{4} + k\pi } \right\}.\)

B \(S = \left\{ {\dfrac{\pi }{4} + k2\pi } \right\}.\)

C \(S = \left\{ {\dfrac{\pi }{4} + k\pi } \right\}.\)

D \(S = \left\{ {\pm \dfrac{\pi }{4} + k\pi } \right\}.\)

A \(S = \left\{ { \dfrac{\pi }{6} + k\pi ;\dfrac{\pi }{2} + k2\pi } \right\}.\)

B \(S = \left\{ { \pm \dfrac{\pi }{6} + k\pi ;\dfrac{\pi }{2} + k2\pi } \right\}.\)

C \(S = \left\{ { \dfrac{\pi }{6} + k\pi ;\dfrac{\pi }{2} + k\pi } \right\}.\)

D \(S = \left\{ { \pm \dfrac{\pi }{6} + k\pi ;\dfrac{\pi }{2} + k\pi } \right\}.\)

A \(S = \left\{ {\dfrac{{k\pi }}{3}} \right\}.\)

B \(S = \left\{ {\dfrac{{k2\pi }}{3}} \right\}.\)

C \(S = \left\{ {\pm \dfrac{{k\pi }}{3}} \right\}.\)

D \(S = \left\{ {\dfrac{{\pi }}{3}} + k \pi \right\}.\)

A \(S = \left\{ { \pm \dfrac{\pi }{3} + k\pi } \right\}.\)

B \(S = \left\{ { \pm \dfrac{\pi }{3} + k2\pi } \right\}.\)

C \(S = \left\{ {  \dfrac{\pi }{3} + k2\pi } \right\}.\)

D \(S = \left\{ {-  \dfrac{\pi }{3} + k2\pi } \right\}.\)

A \(\left[ \begin{array}{l}
x = \dfrac{\pi }{4} + k\pi \\
x = -\arctan \left( {\dfrac{3}{4}} \right) + k\pi 
\end{array} \right.\)

B \(\left[ \begin{array}{l}
x = - \dfrac{\pi }{4} + k\pi \\
x =-\arctan \left( {\dfrac{3}{4}} \right) + k\pi 
\end{array} \right.\)

C \(\left[ \begin{array}{l}
x = \dfrac{\pi }{4} + k\pi \\
x = \arctan \left( {\dfrac{3}{4}} \right) + k\pi 
\end{array} \right.\)

D \(\left[ \begin{array}{l}
x = - \dfrac{\pi }{4} + k\pi \\
x = \arctan \left( {\dfrac{3}{4}} \right) + k\pi
\end{array} \right.\)

A \(\left[ \begin{array}{l}
x = \dfrac{\pi }{4} + k\pi \\
x = \arctan \left( { - 2} \right) + k\pi
\end{array} \right.\)

B \(\left[ \begin{array}{l}
x =- \dfrac{\pi }{4} + k\pi \\
x = \arctan \left( { - 2} \right) + k\pi 
\end{array} \right.\)

C \(\left[ \begin{array}{l}
x = \dfrac{\pi }{4} + k\pi \\
x =- \arctan \left( { - 2} \right) + k\pi 
\end{array} \right.\)

D \(\left[ \begin{array}{l}
x = -\dfrac{\pi }{4} + k\pi \\
x =- \arctan \left( { - 2} \right) + k\pi 
\end{array} \right.\)

A \(\left[ \begin{array}{l}
x = \dfrac{\pi }{3} + k\pi \\
x = - \dfrac{\pi }{3} + k\pi 
\end{array} \right.\)

B \(\left[ \begin{array}{l}
x = \dfrac{\pi }{3} + k2\pi \\
x = - \dfrac{\pi }{3} + k2\pi
\end{array} \right.\)

C \(x = \dfrac{\pi }{3} + k2\pi \)

D \(x =- \dfrac{\pi }{3} + k2\pi \)

A \(\left[ \begin{array}{l}
x = k\pi \\
x =- \dfrac{\pi }{2} + k\pi \\
x = \dfrac{\pi }{6} + k2\pi \\
x = \dfrac{{7\pi }}{6} + k2\pi 
\end{array} \right.\)

B \(\left[ \begin{array}{l}
x = k\pi \\
x = \dfrac{\pi }{2} + k2\pi \\
x =  \dfrac{\pi }{6} + k2\pi \\
x = -\dfrac{{7\pi }}{6} + k2\pi 
\end{array} \right.\)

C \(\left[ \begin{array}{l}
x = k\pi \\
x = -\dfrac{\pi }{2} + k2\pi \\
x = \dfrac{\pi }{6} + k2\pi \\
x = \dfrac{{7\pi }}{6} + k2\pi 
\end{array} \right.\)

D \(\left[ \begin{array}{l}
x = k\pi \\
x = \dfrac{\pi }{2} + k2\pi \\
x = - \dfrac{\pi }{6} + k2\pi \\
x = \dfrac{{7\pi }}{6} + k2\pi
\end{array} \right.\)

A \(\left[ \begin{array}{l}
x = \arccos \dfrac{{\sqrt {17} - 1}}{4} + k2\pi \\
x = - \arccos \dfrac{{\sqrt {17} - 1}}{4} + k2\pi
\end{array} \right.\)

B \(\left[ \begin{array}{l}
x = \arccos \dfrac{{\sqrt {17} - 1}}{4} + k\pi \\
x = - \arccos \dfrac{{\sqrt {17} - 1}}{4} + k\pi 
\end{array} \right.\)

C \(\left[ \begin{array}{l}
x = \arccos \dfrac{{\sqrt {17} + 1}}{4} + k2\pi \\
x = - \arccos \dfrac{{\sqrt {17} + 1}}{4} + k2\pi 
\end{array} \right.\)

D \(\left[ \begin{array}{l}
x = \arccos \dfrac{{\sqrt {17} + 1}}{4} + k\pi \\
x = - \arccos \dfrac{{\sqrt {17} + 1}}{4} + k\pi 
\end{array} \right.\)