- Giải hệ phương trình bằng phương pháp đặt ẩn phụ

A \(\left( {-2; - 1} \right).\)

B \(\left( {2; - 1} \right).\)

C \(\left( {2; \, 1} \right).\)

D \(\left( {-2; \, 1} \right).\)

A \(\left( {x;\,\,y} \right) = \left( {  1;\,\,-2} \right).\)

B \(\left( {x;\,\,y} \right) = \left( {  1;\,\,2} \right).\)

C \(\left( {x;\,\,y} \right) = \left( { - 1;\,\,-2} \right).\)

D \(\left( {x;\,\,y} \right) = \left( { - 1;\,\,2} \right).\)

A \(\left( {3; - 2} \right).\)

B \(\left( {-3; - 2} \right).\)

C \(\left( {3; \, 2} \right).\)

D \(\left( {-3; \, 2} \right).\)

A \(\left( {  1;\,\,-2} \right).\)

B \(\left( { - 1;\,\,-2} \right).\)

C \(\left( { - 1;\,\,2} \right).\)

D \(\left( { 1;\,\,2} \right).\)

A \(\left( {x;\,\,y} \right) = \left( {0;\,\,\frac{5}{2}} \right).\) 

B \(\left( {x;\,\,y} \right) = \left( {0;\,\,-\frac{5}{2}} \right).\) 

C \(\left( {x;\,\,y} \right) = \left( {-\frac{5}{2}};\,\, 0 \right).\) 

D \(\left( {x;\,\,y} \right) = \left( {\frac{5}{2}};\,\, 0 \right).\) 

A \(\left( {x;\,\,y} \right) = \left( {-3; \,\,1} \right).\)

B \(\left( {x;\,\,y} \right) = \left( {-3; - 1} \right).\)

C \(\left( {x;\,\,y} \right) = \left( {3; \,\,1} \right).\)

D \(\left( {x;\,\,y} \right) = \left( {3; - 1} \right).\)

A \(\left( {x;\,\,y} \right) = \left( {-\frac{{21}}{{23}};\frac{{105}}{{53}}} \right).\)

B \(\left( {x;\,\,y} \right) = \left( {\frac{{21}}{{23}};\frac{{105}}{{53}}} \right).\)

C \(\left( {x;\,\,y} \right) = \left( {\frac{{21}}{{23}};-\frac{{105}}{{53}}} \right).\)

D \(\left( {x;\,\,y} \right) = \left( {-\frac{{21}}{{23}};-\frac{{105}}{{53}}} \right).\)

A \(\left( {\sqrt[3]{{\frac{1}{4}}};\sqrt[3]{{\frac{1}{4}}}} \right)\).

B \(\left( {\sqrt[3]{4};\sqrt[3]{4}} \right)\)

C \(\left( {\sqrt[3]{4};\sqrt[3]{4}} \right),\left( {\sqrt[3]{{\frac{1}{4}}};\sqrt[3]{{\frac{1}{4}}}} \right)\).

D Hệ phương trình vô nghiệm.