Đề thi HK2 môn Toán lớp 11 THPT Lê Văn Hưu Thanh...

A \(\angle B'C'A'\)                     

B \(\angle DAC\)                       

C \(\angle C'A'B'\)                     

D \(\angle DCA\)

A \(3\)                                      

B \( - 2018\)                              

C \( - 3\)                                    

D \(1\)

A \(2a + b + c = 1\)               

B \(2a + b + c + 1 = 0\)              

C \(a - b + c + 1 = 0\)                 

D \(a + b + c + 1 = 0\)

A Hàm số \(f\left( x \right) = \dfrac{{x + 1}}{{\sqrt {x - 1} }}\) liên tục trên \(\mathbb{R}\)

B Hàm số \(f\left( x \right) = \dfrac{{x + 1}}{{\sqrt {{x^2} + 1} }}\) liên tục trên \(\mathbb{R}\)

C Hàm số \(f\left( x \right) = \dfrac{{\sqrt {x + 1} }}{{x - 1}}\) liên tục trên \(\mathbb{R}\)      

D Hàm số \(f\left( x \right) = \dfrac{{x + 1}}{{x - 1}}\) liên tục trên \(\mathbb{R}\)

A \(\overrightarrow {AG}  = \dfrac{1}{4}\left( {\overrightarrow {BA}  + \overrightarrow {BC}  + \overrightarrow {BD} } \right)\)  

B \(\overrightarrow {AG}  = \dfrac{1}{3}\left( {\overrightarrow {BA}  + \overrightarrow {BC}  + \overrightarrow {BD} } \right)\)

C \(\overrightarrow {AG}  = \dfrac{1}{4}\left( {\overrightarrow {AB}  + \overrightarrow {AC}  + \overrightarrow {CD} } \right)\)                        

D \(\overrightarrow {AG}  = \dfrac{1}{4}\left( {\overrightarrow {AB}  + \overrightarrow {AC}  + \overrightarrow {AD} } \right)\)

A \(\cos \varphi  = \dfrac{1}{4}\)                                

B \(\varphi  = {60^0}\)              

C \(\varphi  = {30^0}\)

D \(\cos \varphi  = \dfrac{3}{4}\)

A \(\left( {ACD} \right) \bot \left( {AIB} \right)\)   

B \(\left( {BCD} \right) \bot \left( {AIB} \right)\)

C Góc giữa hai mặt phẳng \(\left( {ACD} \right)\) và \(\left( {BCD} \right)\) là góc \(AIB\).

D Góc giữa hai mặt phẳng \(\left( {ABC} \right)\) và \(\left( {ABD} \right)\) là góc \(CBD\).

A \(y = x\cos x\)                     

B \(y = 2x\sin x\)                       

C \(y = x\sin x\)                         

D \(y = 2x\cos x\)

A \(\left( {\dfrac{u}{v}} \right)' = \dfrac{{u'v + uv'}}{{{v^2}}}\) 

B \(\left( {{x^3}} \right)' =  - 3{x^2}\)                                  

C \(\left( {\sqrt x } \right)' = \dfrac{1}{{2\sqrt x }}\)            

D \(\left( {uv} \right)' = u'v - uv'\)

A \( - 1 \le a \le 1\)              

B \(1 \le a < 2\)                         

C \(a \ge 2\)                              

D \(a <  - 1\)

A 3

B 1

C 4

D 2

A       \(f'\left( {{x_0}} \right) = \mathop {\lim }\limits_{x \to 0} \dfrac{{f\left( {{x_0} + h} \right) - f\left( {{x_0}} \right)}}{h}\) 

B \(f'\left( {{x_0}} \right) = \mathop {\lim }\limits_{x \to 0} \dfrac{{f\left( {x + {x_0}} \right) - f\left( {{x_0}} \right)}}{{x - {x_0}}}\)

C       \(f'\left( {{x_0}} \right) = \mathop {\lim }\limits_{\Delta x \to 0} \dfrac{{f\left( {{x_0} + \Delta x} \right) - f\left( {{x_0}} \right)}}{{\Delta x}}\)                                  

D \(f'\left( {{x_0}} \right) = \mathop {\lim }\limits_{x \to 0} \dfrac{{f\left( x \right) - f\left( {{x_0}} \right)}}{{x - {x_0}}}\)

A 2

B 1

C 3

D 0

A \(y = 2{x^2} + x - 2018\)  

B \(y =  - 2{x^2} + x\)                 

C \(y = 3{x^3} + {x^2}\)             

D \(y =  - 2{x^2} - x + 2017\)

A \(\lim \dfrac{{{n^2} - 1}}{{\sqrt {{n^2} + 1} }}\)   

B \(\lim \dfrac{{2n - 7}}{{\sqrt {{n^3} + 1} }}\)                    

C \(\lim \left( {1 - 8n} \right)\)  

D \(\lim \dfrac{{n - 1}}{{\sqrt {{n^2} + n} }}\)

A \(I = 23\)                              

B \(I = 19\)                                

C \(I =  - 19\)                             

D \(I =  - 23\)

A \(18A\)                                  

B \(20A\)                                   

C \(28A\)                                   

D \(34A\)

A \(7\)                                      

B \(8\)                                       

C \(\dfrac{{11}}{2}\)                  

D \(4\)

A \( - 3\)                                  

B \(3\)                                       

C \(20\)                                     

D \(15\)

A \(\overrightarrow {B'A'} \)

B \(\overrightarrow {D'C'} \)     

C \(\overrightarrow {CD} \)      

D \(\overrightarrow {BA} \)

A  \(\overrightarrow {AM}  = \overrightarrow a  - \overrightarrow c  + \dfrac{1}{2}\overrightarrow b \)

B \(\overrightarrow {AM}  = \overrightarrow b  - \overrightarrow a  + \dfrac{1}{2}\overrightarrow c \)       

C \(\overrightarrow {AM}  = \overrightarrow b  + \overrightarrow c  - \dfrac{1}{2}\overrightarrow a \)       

D \(\overrightarrow {AM}  = \overrightarrow a  + \overrightarrow c  - \dfrac{1}{2}\overrightarrow b \)

A \({45^0}\)                             

B \({30^0}\)                               

C \({60^0}\)                               

D \({90^0}\)

A \(3\)                                      

B \(\dfrac{5}{3}\)                      

C \(\dfrac{{10}}{3}\)                  

D \(5\)

A \(y'' =  - 2\cos 2x\)            

B \(y'' = 2\cos 2x\)                    

C \(y'' = 2\sin 2x\)                     

D \(y'' =  - 2\sin 2x\)

A \( - \dfrac{1}{2}\)

B \( \dfrac{1}{2}\)

C \(+\infty\)

D \(-\infty\)

A \(+ \infty \).

B \(0\)

C \(- \infty \).

D \(1\)

A \(+\infty\)

B \(-\infty\)

C \(-2\)

D \(2\)

A \(y=- 8x + \dfrac{8}{3}\)

B \(y=- 8x - \dfrac{8}{3}\)

C \(y=8x - \dfrac{8}{3}\)

D \(y= 8x + \dfrac{8}{3}\)