Bài 6 trang 34 - sách giáo khoa Hóa 12
\(n_{C_{12}H_{22}O_{11}} = \dfrac {100} {342} = x (mol)\)
\(C_{12}H_{22}O_{11} + H_2O \rightarrow C_6H_{12}O_6 + C_6H_{12}O_6\)
xmol xmol xmol
\(CH_2OH- [CHOH]_3- CO- CH_2OH \xrightarrow[]{OH^-} CH_2OH- [CHOH]_4- CHO\)
a mol a mol
\(C_5H_{11}O_5CH=O + 2AgNO_3 + 3NH_3 + H_2O \rightarrow C_5H_{11}O_5COONH_4 + 2Ag\downarrow + 2NH_4NO_3\)
2x mol 4x mol 4x mol
\(m_{AgNO_3} = \dfrac {4 \times 100} {342} \times 170 = 198,83 (g)\)
\(m_{Ag} = \dfrac {4 \times 100} {342} \times 108 = 126,31 (g)\)