Đề thi chính thức vào 10 môn Toán Sở GD&ĐT Hà Nam...

A \(\begin{array}{l}1)\,\,S = \left\{ { - 1;\, - 5} \right\}\\2)\,\,\left( {x;\,y} \right) = \left( {10;\,15} \right)\end{array}\)

B \(\begin{array}{l}1)\,\,S = \left\{ {1;\, - 5} \right\}\\2)\,\,\left( {x;\,y} \right) = \left( {10;\,5} \right)\end{array}\)

C \(\begin{array}{l}1)\,\,S = \left\{ {1;\,5} \right\}\\2)\,\,\left( {x;\,y} \right) = \left( {15;\,10} \right)\end{array}\)

D \(\begin{array}{l}1)\,\,S = \left\{ { - 1;\,5} \right\}\\2)\,\,\left( {x;\,y} \right) = \left( {10;\,5} \right)\end{array}\)

A \(\begin{array}{l}1)\,\,A = 2\sqrt 2 \\2)\,\,B = \frac{1}{{\sqrt a  + 3}};\,\,\,a \in \left\{ {8;\,11;\,12} \right\}\end{array}\)

B \(\begin{array}{l}1)\,\,A = 3\sqrt 2 \\2)\,\,B = \frac{{11}}{{a - 9}};\,\,\,a \in \left\{ {8;\,10;\,20} \right\}\end{array}\)

C \(\begin{array}{l}1)\,\,A = \sqrt 2 \\2)\,\,B = \frac{{11}}{{a - 9}};\,\,\,a \in \left\{ {8;\,11;\,20} \right\}\end{array}\)

D \(\begin{array}{l}1)\,\,A = 3\sqrt 2 \\2)\,\,B = \frac{{11}}{{\sqrt a  - 3}};\,\,\,a \in \left\{ {8;\,11;\,20} \right\}\end{array}\)

A \(\begin{array}{l}1)\,\,A\left( {2;\,4} \right) \in \left( P \right)\\2)\,\,\left[ \begin{array}{l}m = 0\\m = 4\end{array} \right.\end{array}\)

B \(\begin{array}{l}1)\,\,A\left( {2;\,4} \right) \notin \left( P \right)\\2)\,\,\left[ \begin{array}{l}m = 2\\m = 4\end{array} \right.\end{array}\)

C \(\begin{array}{l}1)\,\,A\left( {2;\,4} \right) \in \left( P \right)\\2)\,\,\left[ \begin{array}{l}m = 2\\m = 4\end{array} \right.\end{array}\)

D \(\begin{array}{l}1)\,\,A\left( {2;\,4} \right) \notin \left( P \right)\\2)\,\,\left[ \begin{array}{l}m = 0\\m = 4\end{array} \right.\end{array}\)