Đề thi chính thức vào 10 môn Toán Sở GD&ĐT Thái Bì...

A \(\begin{array}{l}a)\,x\, \ge \, - \frac{3}{5}\\b)\,\,D\left( { - 2;\,2} \right)\\c)\,\,a = 2;\,\,b = 0\end{array}\)

B \(\begin{array}{l}a)\,x\, \ge \,\frac{3}{5}\\b)\,\,D\left( { - 2;\,4} \right)\\c)\,\,a = 2;\,\,b = 0\end{array}\)

C \(\begin{array}{l}a)\,x\, \ge \, - \frac{3}{5}\\b)\,\,D\left( { - 2;\, - 2} \right)\\c)\,\,a = 2;\,\,b = 1\end{array}\)

D \(\begin{array}{l}a)\,x\, \ge \,\frac{3}{5}\\b)\,\,D\left( { - 2;\,2} \right)\\c)\,\,a = 2;\,\,b = 2\end{array}\)

A \(\begin{array}{l}a)\,\,P = 2\sqrt y  + y\\b)\,\,P\,\, \le \,\,1\end{array}\)

B \(\begin{array}{l}a)\,\,P = 2\sqrt y  - y\\b)\,\,P\,\, \le \,\,1\end{array}\)

C \(\begin{array}{l}a)\,\,P = 2\sqrt x  - y\\b)\,\,P\,\, \le \,\,1\end{array}\)

D \(\begin{array}{l}a)\,\,P = \sqrt y  - y\\b)\,\,P\,\, \le \,\,1\end{array}\)

A \(\begin{array}{l}a)\,\,S = \left\{ { - \sqrt 2 ;\,\,\sqrt 2 } \right\}\\b)\,\,m =  \pm \frac{1}{2}\end{array}\)

B \(\begin{array}{l}a)\,\,S = \left\{ { \pm 2} \right\}\\b)\,\,m =  \pm 1\end{array}\)

C \(\begin{array}{l}a)\,\,S = \left\{ {2 - \sqrt 2 ;\,\,2 + \sqrt 2 } \right\}\\b)\,\,m =  \pm \frac{1}{2}\end{array}\)

D \(\begin{array}{l}a)\,\,S = \left\{ {2 - \sqrt 2 ;\,\,2 + \sqrt 2 } \right\}\\b)\,\,m =  \pm 1\end{array}\)

A \(S = \left\{ {\frac{{ - 11 \pm \sqrt {73} }}{6};\,\frac{{ - 13 \pm \sqrt {69} }}{6}} \right\}\)

B \(S = \left\{ {\frac{{ - 11 - \sqrt {73} }}{6};\,\frac{{ - 13 + \sqrt {69} }}{6}} \right\}\)

C \(S = \left\{ {\frac{{ - 13 + \sqrt {69} }}{6};\,\frac{{ - 13 - \sqrt {69} }}{6}} \right\}\)

D \(S = \left\{ {\frac{{ - 11 + \sqrt {73} }}{6};\,\frac{{ - 13 - \sqrt {69} }}{6}} \right\}\)