Đề ôn tập chương 4 Đại số Toán 9 có đáp án Trường...

A.  \(\left[\begin{array}{l} x_{1}=\frac{3}{4} \\ x_{2}=6 \end{array}\right.\)

B.  \(\left[\begin{array}{l} x_{1}=\frac{3}{4} \\ x_{2}=-6 \end{array}\right.\)

C.  \(\left[\begin{array}{l} x_{1}=-\frac{3}{4} \\ x_{2}=-6 \end{array}\right.\)

D. Vô nghiệm.

A. Vô nghiệm.

B.  \(\left[\begin{array}{l} x_{1}=-1 \\ x_{2}=\frac{2}{3} \end{array}\right.\)

C.  \(\left[\begin{array}{l} x_{1}=1 \\ x_{2}=\frac{2}{3} \end{array}\right.\)

D.  \(\left[\begin{array}{l} x_{1}=-2 \\ x_{2}=\frac{2}{3} \end{array}\right.\)

A. Vô nghiệm.

B.  \(\left[\begin{array}{l} x_{1}=\frac{1}{4} \\ x_{2}=-3 \end{array}\right.\)

C.  \(\left[\begin{array}{l} x_{1}=\frac{1}{3} \\ x_{2}=-3 \end{array}\right.\)

D.  \(\left[\begin{array}{l} x_{1}=\frac{1}{4} \\ x_{2}=3 \end{array}\right.\)

A.  \(\left[\begin{array}{l} x_{1}=-1 \\ x_{2}=-\frac{5}{2} \end{array}\right.\)

B.  \(\left[\begin{array}{l} x_{1}=-1 \\ x_{2}=\frac{5}{2} \end{array}\right.\)

C.  \(\left[\begin{array}{l} x_{1}=2 \\ x_{2}=\frac{5}{2} \end{array}\right.\)

D.  \(\left[\begin{array}{l} x_{1}=-1 \\ x_{2}=\frac{3}{2} \end{array}\right.\)

A.  \(\left[\begin{array}{l} x_{1}=\frac{7+\sqrt{69}}{5} \\ x_{2}=\frac{7-\sqrt{69}}{5} \end{array}\right.\)

B.  \(\left[\begin{array}{l} x_{1}=\frac{-7+\sqrt{69}}{5} \\ x_{2}=\frac{-7-\sqrt{69}}{5} \end{array}\right.\)

C.  \(\left[\begin{array}{l} x_{1}=\frac{-7+\sqrt{69}}{10} \\ x_{2}=\frac{-7-\sqrt{69}}{10} \end{array}\right.\)

D.  \(\left[\begin{array}{l} x_{1}=\frac{7+\sqrt{69}}{10} \\ x_{2}=\frac{7-\sqrt{69}}{10} \end{array}\right.\)

A.  \(\left[\begin{array}{l} x_{1}=3 \\ x_{2}=-13 \end{array}\right.\)

B.  \(\left[\begin{array}{l} x_{1}=-3 \\ x_{2}=-13 \end{array}\right.\)

C.  \(\left[\begin{array}{l} x_{1}=3 \\ x_{2}=-11 \end{array}\right.\)

D.  \(\left[\begin{array}{l} x_{1}=-3 \\ x_{2}=-11 \end{array}\right.\)

A.  \(\left[\begin{array}{l} x_{1}=\frac{1}{2} \\ x_{2}=-3 \end{array}\right.\)

B.  \(\left[\begin{array}{l} x_{1}=\frac{1}{3} \\ x_{2}=3 \end{array}\right.\)

C.  \(\left[\begin{array}{l} x_{1}=\frac{1}{3} \\ x_{2}=-3 \end{array}\right.\)

D. Vô nghiệm.

A.  \(\left[\begin{array}{l} x_{1}=1+2 \sqrt{3} \\ x_{2}=1-2 \sqrt{2} \end{array}\right.\)

B.  \(\left[\begin{array}{l} x_{1}=-1+2 \sqrt{3} \\ x_{2}=-1-2 \sqrt{2} \end{array}\right.\)

C. x=0

D. x=2

A.  \(\left[\begin{array}{l} x_{1}=\sqrt{3}-1 \\ x_{2}=\sqrt{3}-3 \end{array}\right.\)

B.  \(\left[\begin{array}{l} x_{1}=\sqrt{3}+1 \\ x_{2}=\sqrt{3}-3 \end{array}\right.\)

C. Vô nghiệm.

D.  \(\left[\begin{array}{l} x_{1}=-\sqrt{3}+1 \\ x_{2}=-\sqrt{3}-3 \end{array}\right.\)

A.  \(\left[\begin{array}{l} x_{1}=\sqrt{2}+1 \\ x_{2}=1-\sqrt{2} \end{array}\right.\)

B.  \(\left[\begin{array}{l} x_{1}=-\sqrt{2}+1 \\ x_{2}=-\sqrt{2}-1 \end{array}\right.\)

C. Vô nghiệm.

D.  \(\left[\begin{array}{l} x_{1}=\sqrt{2}+1 \\ x_{2}=\sqrt{2}-1 \end{array}\right.\)

A. \({x_1} + {x_2} =  - \dfrac{r}{p};\,\,{x_1}{x_2} = \dfrac{q}{p}\)

B. \({x_1} + {x_2} = \dfrac{q}{p};\,\,{x_1}{x_2} = \dfrac{r}{p}\)

C. \({x_1} + {x_2} =  - \dfrac{q}{p};\,\,{x_1}{x_2} = \dfrac{r}{p}\)

D. \({x_1} + {x_2} = \dfrac{q}{p};\,\,{x_1}{x_2} =  - \dfrac{r}{p}\)

A. \(x = \dfrac{{4 + \sqrt 5 }}{2};x = \dfrac{{4 - \sqrt 5 }}{2}\)

B. \(x = \dfrac{{3 + \sqrt 5 }}{2};x = \dfrac{{4 - \sqrt 5 }}{2}\)

C. \(x = \dfrac{{4 + \sqrt 5 }}{2};x = \dfrac{{3 - \sqrt 5 }}{2}\)

D. \(x = \dfrac{{3 + \sqrt 5 }}{2};x = \dfrac{{3 - \sqrt 5 }}{2}\)

A. Phương trình vô nghiệm 

B. x = 1; x = -1

C. x = 5; x = -5

D. x = 8; x = -8

A. \(40\left( {km/h} \right)\)

B. \(45\left( {km/h} \right)\)

C. \(50\left( {km/h} \right)\)

D. \(55\left( {km/h} \right)\)