Cho 16,0 gam hỗn hợp gồm Na và Al vào nước dư, thu...

A

- Hướng dẫn giải

2Na + 2H₂O → 2NaOH + H₂

2Al + 2H₂O + 2NaOH → 2NaAlO₂ + 3H₂

n_Na = n_{Al pư} = \(% MathType!MTEF!2!1!+- % feaahqart1ev3aaatCvAUfeBSjuyZL2yd9gzLbvyNv2Caerbw5usTq % vATv2CaeXatLxBI9gBaerbd9wDYLwzYbItLDharuavP1wzZbItLDhi % s9wBH5garqqtubsr4rNCHbGeaGqiVu0Je9sqqrpepC0xbbL8F4rqqr % Ffpeea0xe9Lq-Jc9vqaqpepm0xbba9pwe9Q8fs0-yqaqpepae9pg0F % irpepeKkFr0xfr-xfr-xb9adbaqaaeGaciGaaiaabeqaamaaeaqbaa % GcbaWaaSaaaeaacaaIYaGaamOBamaaBaaaleaacaWGibWaaSbaaWqa % aiaaikdaaeqaaaWcbeaaaOqaaiaaisdaaaaaaa!3D9D! \frac{{2{n_{{H_2}}}}}{4}\) = 0,16

→ m = 16 – 0,16(23 + 27) = 8 gam