Cho \(\mathop {\lim }\limits_{x \to {2^ + }} \left...

C

- Hướng dẫn giải

\(\mathop {\lim }\limits_{x \to {2^ + }} \left( {x - 2} \right)\sqrt {\frac{x}{{{x^2} - 4}}}  = \mathop {\lim }\limits_{x \to {2^ + }} \sqrt {\frac{{x.{{\left( {x - 2} \right)}^2}}}{{{x^2} - 4}}}  = \mathop {\lim }\limits_{x \to 2 + } \sqrt {\frac{{\left( {x - 2} \right)x}}{{x + 2}}}  = 0\)