Cho hình lăng trụ ABC.A’B’C’, M là trung...

D

- Hướng dẫn giải

Ta có:

\(\begin{array}{l}
{V_{M.ABC}} = \frac{1}{3}d\left( {M;\left( {ABC} \right)} \right).{S_{\Delta ABC}} = \frac{1}{3}.\frac{1}{2}d\left( {C';\left( {ABC} \right)} \right).{S_{\Delta ABC}} = \frac{1}{6}{V_{ABC.A'B'C'}}\\
 \Rightarrow {V_1} = \frac{1}{6}{V_{ABC.A'B'C'}} \Rightarrow {V_2} = \frac{5}{6}{V_{ABC.A'B'C'}} \Rightarrow \frac{{{V_1}}}{{{V_2}}} = \frac{1}{5}
\end{array}\)