Cho \(\frac{{\log a}}{p} = \frac{{\log b}}{q} = \f...

Câu hỏi: Cho \(\frac{{\log a}}{p} = \frac{{\log b}}{q} = \frac{{\log c}}{r} = \log x \ne 0;\frac{{{b^2}}}{{ac}} = {x^y}\). Tính \(y\) theo \(p, q, r\).

A. \(y = {q^2} - pr\)

B. \(y = \frac{{p + r}}{{2q}}\)

C. \(y = 2q - p - r\)

D. \(y = 2q - p - r\)