Amino axit X chứa a nhóm –COOH và b nhóm – NH2. Ch...

A

- Hướng dẫn giải

\(X:{(COOH)_a}R{(N{H_2})_b};{n_X} = 1(mol) \to {n_{HCl}} = b(mol)\)

\(BTKL:{m_X} + {m_{HCl}} = {m_{muoi}} \to {M_X}.1 + b.36,5 = 169,5(1)\)

\({n_X} = 1(mol) \to {n_{NaOH}} = a(mol)\)

\(BTKL:{m_X} + {m_{NaOH}} = {m_{muoi}} + {m_{{H_2}O}} \to {M_X} + 40a = 177 + 18a\)

\( \to {M_X} + 22a = 177(2)\xrightarrow{{(1),(2)}}22a - 36,5b = 7,5\)

\(\to \left\{ \begin{gathered} b = 1 \hfill \\ a = 2 \hfill \\ \end{gathered} \right. \to {M_X} = 133;CT:{C_x}{H_y}N{O_4} \to 12x + y = 55 \to \left\{ \begin{gathered} x = 4 \hfill \\ y = 7 \hfill \\ \end{gathered} \right.\)