\(\mathop {\lim }\limits_{x \to  + \infty } \frac{...

A

- Hướng dẫn giải

\(\mathop {\lim }\limits_{x \to  + \infty } \frac{{2{x^2} - 3}}{{{x^6} + 5{x^5}}} = \mathop {\lim }\limits_{x \to  + \infty } \frac{{\frac{2}{{{x^4}}} - \frac{3}{{{x^6}}}}}{{1 + \frac{5}{x}}} = \frac{0}{1} = 0\)