Thủy phân 0,2 mol etyl axetat trong môi trường ax...

B

- Hướng dẫn giải

Đáp án B\(\begin{align}C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}+{{H}_{2}}O\overset{H2SO4}\leftrightarrows C{{H}_{3}}COOH+{{C}_{2}}{{H}_{5}}OH \\(mol)\,\,\,\,\,0,2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\to 0,2 \\\end{align}\). \(H\% = \dfrac{{m\,{\,_{thuc.te}}}}{{m\,{\,_{ly\,thuyet}}}}.100\) \(= > m\,{\,_{thuc.te}} = m\,{\,_{ly\,thuyet}}.\dfrac{{H\% }}{{100}} = 0,2.46.\frac{{80}}{{100}} = 7,36gam\)