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- Hướng dẫn giải

$m_{H_2}=n_{H_2}.M_{H_2}$ = 2.2 = 4(g) $\to V_{H_2}=n_{H_2}$.22,4 = 2.22,4 = 44,8(l)

$m_{O_2}=n_{O_2}.M_{O_2}$ = 1,5.32 = 48(g) $\to V_{O_2}=n_{O_2}$.22,4 = 1,5.22,4 = 33,6(l)

$m_{C{O}_2}=n_{C{O}_2}.M_{C{O}_2}$ = 1,15.44 = 50,6(g) $\to V_{C{O}_2}=n_{C{O}_2}$.22,4 = 1,15.22,4 = 25,76(l)

$m_{C{H}_4}=n_{C{H}_4}.M_{C{H}_4}$= 1,15.16 = 18,4(g) $\to V_{C{H}_4}=n_{C{H}_4}$.22,4 = 1,15.22,4 = 25,76(l)