Cho

Câu hỏi: Cho ${\int }_{-1}^2\mathrm{f}\left(\mathrm{x}\right)\mathrm{dx}=2$ và ${\int }_{-1}^2\mathrm{g}\left(\mathrm{x}\right)\mathrm{dx}=-1.$ Tính $\mathrm{I}={\int }_{-1}^2[\mathrm{x}+2\mathrm{f}(\mathrm{x})+3\mathrm{g}(\mathrm{x}\left)\right]\mathrm{dx}$ bằng

$\mathbf{A}\mathbf{.} \mathrm{I}=\frac{11}{2}.$

$\mathbf{B}\mathbf{.} \mathrm{I}=\frac{7}{2}.$

$\mathbf{C}\mathbf{.} \mathrm{I}=\frac{17}{2}.$

$\mathbf{D}\mathbf{.} \mathrm{I}=\frac{5}{2}.$