Tích phân

Câu hỏi: Tích phân ${\int }_0^{\pi }\sqrt{1-\cos 2x}dx$$+{\int }_0^{2\mathrm{\pi }}\sqrt{1-\cos 2x}dx$$+{\int }_0^{4\mathrm{\pi }}\sqrt{1-\cos 2x}dx+$$...+{\int }_0^{2^{2018}\mathrm{\pi }}\sqrt{1-\cos 2x}dx$ bằng

A. $\left(2^{2019}-2\right)\sqrt{2}$

B. $\left(2^{2018}-1\right)\sqrt{2}$

C. $\left(2^{2019}-1\right)\sqrt{2}$

D. $\left(2^{2020}-2\right)\sqrt{2}$