Tìm hàm số

Câu hỏi: Tìm hàm số $\mathrm{y}=\mathrm{f}\left(\mathrm{x}\right)$ nếu biết $\mathrm{dy}=6\mathrm{x}{\left(3{\mathrm{x}}^2-1\right)}^3\mathrm{dx}$ và $\mathrm{f}\left(0\right)=1$

A. $\mathrm{y}=\frac{{\left(3{\mathrm{x}}^2-1\right)}^4}{4}+\frac{5}{4}$

B. $\mathrm{y}=\frac{{\left(3{\mathrm{x}}^2-1\right)}^4}{3}+\frac{2}{3}$

C. $\mathrm{y}=\frac{{\left(3{\mathrm{x}}^2-1\right)}^4}{4}+\frac{3}{4}$

D. $\mathrm{y}=\frac{{\left(3{\mathrm{x}}^2-1\right)}^4}{2}+\frac{1}{2}$