Cho

Câu hỏi: Cho $a={\log }_{4}3, b={\log }_{25}2$. Hãy tính ${\log }_{60}\sqrt{150}$ theo a, b

A. ${\log }_{60}\sqrt{150}$$=\frac{1}{2}.\frac{2+2b+ab}{1+4b+2ab}$

B. ${\log }_{60}\sqrt{150}$$=\frac{2+2b+ab}{1+4b+2ab}$

C. ${\log }_{60}\sqrt{150}$$=\frac{1}{4}.\frac{2+2b+ab}{1+4b+2ab}$

D. ${\log }_{60}\sqrt{150}$$=4.\frac{2+2b+ab}{1+4b+2ab}$