Cho F(x) là nguyên hà...

Câu hỏi: Cho F(x) là nguyên hàm của hàm số $\mathrm{f}\left(\mathrm{x}\right)=\frac{{\left(2\mathrm{x}+1\right)}^8}{{\left(\mathrm{x}+1\right)}^{10}}$ thỏa mãn F(0)=1. Tìm hàm số F(x).

A. $\mathrm{F}\left(\mathrm{x}\right)=\frac{1}{8}{\left(\frac{2\mathrm{x}+1}{\mathrm{x}+1}\right)}^8+\frac{7}{8}$

B. $\mathrm{F}\left(\mathrm{x}\right)=\frac{1}{9}\ln \left(\frac{2\mathrm{x}+1}{\mathrm{x}+1}\right)+\frac{8}{9}$

C. $\mathrm{F}\left(\mathrm{x}\right)=\frac{1}{9}{\left(\frac{2\mathrm{x}+1}{\mathrm{x}+1}\right)}^9+\frac{8}{9}$

D. $\mathrm{F}\left(\mathrm{x}\right)=-\frac{1}{9}{\left(\frac{\mathrm{x}+1}{2\mathrm{x}+1}\right)}^9+\frac{10}{9}$