Trong không gian Oxy cho ba vecto 

Câu hỏi: Trong không gian Oxy cho ba vecto $\stackrel{\rightharpoonup }{a}=\left(2;-5;3\right)$;$\stackrel{\rightharpoonup }{b}=\left(0;2;-1\right)$;$\stackrel{\rightharpoonup }{c}=\left(1;7;2\right)$. Tọa độ của vecto $\stackrel{\rightharpoonup }{u}=4\stackrel{\rightharpoonup }{a}-\frac{\stackrel{\rightharpoonup }{b}}{3}+3\stackrel{\rightharpoonup }{c}$, là:

A. $\stackrel{\rightharpoonup }{u}=\left(11;\frac{1}{3};\frac{55}{3}\right)$

B. $\stackrel{\rightharpoonup }{u}=\left(-11;\frac{1}{3};\frac{55}{3}\right)$

C. $\stackrel{\rightharpoonup }{u}=\left(11;\frac{-1}{3};\frac{55}{3}\right)$

D. $\stackrel{\rightharpoonup }{u}=\left(11;\frac{-1}{3};\frac{-55}{3}\right)$