Cho

Câu hỏi: Cho $\mathrm{a}={\log }_{2}3$và $\mathrm{b}={\log }_{3}5$. Tính ${\log }_{6}45$

A. ${\log }_{6}45=\frac{\mathrm{a}\left(1+\mathrm{b}\right)}{1+\mathrm{a}}$

B. ${\log }_{6}45=\frac{\mathrm{a}\left(2+\mathrm{b}\right)}{1+\mathrm{a}}$

C. ${\log }_{6}45=\frac{2\mathrm{a}\left(1+\mathrm{b}\right)}{1+\mathrm{a}}$

D. ${\log }_{6}45=\frac{\mathrm{ab}+2}{1+\mathrm{a}}$