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B

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Đáp án B

$$\begin{gathered} A=\frac{1,6:\left(1{\displaystyle \frac{3}{5}}.1,25\right)}{0,64-{\displaystyle \frac{1}{25}}}+\frac{\left(1,08-{\displaystyle \frac{2}{25}}\right):{\displaystyle \frac{4}{7}}}{\left(5{\displaystyle \frac{5}{9}}-2{\displaystyle \frac{1}{4}}\right).2{\displaystyle \frac{2}{17}}}+0,6+0,5:\frac{2}{5} \\ =\frac{{\displaystyle \frac{8}{5}}:\left({\displaystyle \frac{8}{5}}.{\displaystyle \frac{5}{4}}\right)}{{\displaystyle \frac{16}{25}}-{\displaystyle \frac{1}{25}}}+\frac{\left({\displaystyle \frac{27}{25}}-{\displaystyle \frac{2}{25}}\right):{\displaystyle \frac{4}{7}}}{\left({\displaystyle \frac{50}{9}}-{\displaystyle \frac{9}{4}}\right).{\displaystyle \frac{36}{17}}}+\frac{3}{5}.\frac{1}{2}:\frac{2}{5} \\ =\frac{{\displaystyle \frac{4}{5}}}{{\displaystyle \frac{3}{5}}}+\frac{{\displaystyle \frac{7}{4}}}{7}+\frac{3}{5}.\frac{1}{2}:\frac{2}{5} \\ =\frac{4}{3}+\frac{1}{4}+\frac{3}{5}.\frac{1}{2}:\frac{2}{5} \\ =\frac{4}{3}+\frac{1}{4}+\frac{3}{5}.\frac{1}{2}.\frac{5}{2} \\ =\frac{7}{3} \end{gathered}$$