Tính tổng \(S = C_{2018}^0 + \dfrac{1}{2}C_{2018}^...

Câu hỏi: Tính tổng \(S = C_{2018}^0 + \dfrac{1}{2}C_{2018}^1 + \dfrac{1}{3}C_{2018}^2 + ... + \dfrac{1}{{2018}}C_{2018}^{2017} + \dfrac{1}{{2019}}C_{2018}^{2018}\)

A \(S = \dfrac{{{2^{2018}} + 1}}{{2019}}\)

B \(S = \dfrac{{{2^{2018}} - 1}}{{2019}} + 1\)

C \(S = \dfrac{{{2^{2019}} - 1}}{{2019}}\)

D \(S = \dfrac{{{2^{2018}} - 1}}{{2019}} - 1\)