Phân tích đa thức thành nhân tử:\(a)\ 15{{x}^{2}}+...

Câu hỏi: Phân tích đa thức thành nhân tử:\(a)\ 15{{x}^{2}}+10xy\)                                                                  \(b)\ 35x\left( y-8 \right)-14y\left( 8-y \right)\)\(c)\ -x+6{{x}^{2}}y-12xy+2\)                                                          \(d)\ {{x}^{3}}-{{x}^{2}}+x-1\)

A \(\begin{array}{l}
a)\,\,5x\left( {3x + 2y} \right)\\
b)\,\,\left( {5x + 2y} \right)\left( {y - 8} \right)\\
c)\,\,\left( {6xy - 1} \right)\left( {x - 2} \right)\\
d)\,\,\,\left( {{x^2} + 1} \right)\left( {x - 1} \right)
\end{array}\)

B \(\begin{array}{l}
a)\,\,5x\left( {3x + 2y} \right)\\
b)\,\,7\left( {5x + 2y} \right)\left( {y - 8} \right)\\
c)\,\,\left( {6xy - 1} \right)\left( {x - 2} \right)\\
d)\,\,\,\left( {{x^2} + 1} \right)\left( {x + 1} \right)
\end{array}\)

C \(\begin{array}{l}
a)\,\,5x\left( {3x + 2y} \right)\\
b)\,\,7\left( {5x + 2y} \right)\left( {y - 8} \right)\\
c)\,\,\left( {6xy - 1} \right)\left( {x - 2} \right)\\
d)\,\,\,\left( {{x^2} + 1} \right)\left( {x - 1} \right)
\end{array}\)

D \(\begin{array}{l}
a)\,\,5x\left( {3x - 2y} \right)\\
b)\,\,7\left( {5x + 2y} \right)\left( {y - 8} \right)\\
c)\,\,\left( {6xy - 1} \right)\left( {x - 2} \right)\\
d)\,\,\,\left( {{x^2} + 1} \right)\left( {x - 1} \right)
\end{array}\)