Cho 0,64 gam Cu tác dụng với axit HNO3...

C

- Hướng dẫn giải

Phương pháp giải:

\(\begin{gathered}
Cu - 2{\text{e}} \to \mathop {Cu}\limits^{ + 2} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\mathop N\limits^{ + 5} + 1{\text{e}} \to \mathop N\limits^{ + 4} {O_2} \hfill \\
0,01\,\,\,0,02\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,02\,\,\,\,\,\,\,\,0,02 \hfill \\
\end{gathered} \)

=> V_NO2

Giải chi tiết:

\(\begin{gathered}
Cu - 2{\text{e}} \to \mathop {Cu}\limits^{ + 2} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\mathop N\limits^{ + 5} + 1{\text{e}} \to \mathop N\limits^{ + 4} {O_2} \hfill \\
0,01\,\,\,0,02\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,02\,\,\,\,\,\,\,\,0,02 \hfill \\ 
\end{gathered} \)

=> V_NO2 = 0,02.22,4=0,448 lít = 448 ml

Đáp án C