Cho hàm số \(f\left( x \right) = \left\{ \begin{a...
Câu hỏi: Cho hàm số \(f\left( x \right) = \left\{ \begin{array}{l}x + 2\sqrt {1 - x} \,\,\,\,\,khi\,\,\,x \le 1\\\frac{{x + 3}}{{x + 1}}\,\,\,\,khi\,\,\,1 < x \le 5\end{array} \right..\)
A \(\begin{array}{l}D = \left( { - \infty ;\,\,5} \right]\\f\left( { - 3} \right) = 1\,\,\,;\,\,\,f\left( 1 \right) = 1\\f\left( 2 \right) = \frac{5}{3}\,\,\,;\,\,\,f\left( 5 \right) = \frac{4}{3}\end{array}\)
B \(\begin{array}{l}D = \left( { - \infty ;\,\,1} \right]\\f\left( { - 3} \right) = 0\,\,\,;\,\,\,f\left( 1 \right) = 2\\f\left( 2 \right) = \frac{5}{3}\,\,\,;\,\,\,f\left( 5 \right) = \frac{4}{3}\end{array}\)
C \(\begin{array}{l}D = \left( {1;5} \right]\\f\left( { - 3} \right) = 0\,\,\,;\,\,\,f\left( 1 \right) = 2\\f\left( 2 \right) = 3\,\,\,;\,\,\,f\left( 5 \right) = \frac{3}{2}\end{array}\)
D \(\begin{array}{l}D = \left( {5; + \infty } \right)\\f\left( { - 3} \right) = 1\,\,\,;\,\,\,f\left( 1 \right) = 1\\f\left( 2 \right) = 2\,\,\,;\,\,\,f\left( 5 \right) = \frac{3}{2}\end{array}\)
A \(M,N\)
B \(M,P\)
C \(N,P\)
D \(M,N,P\)
Câu hỏi trên thuộc đề trắc nghiệm
40 bài tập trắc nghiệm hàm số