Cho tổng: \({S_n} = \frac{1}{{1.5}} + \frac{1}{{5....

Câu hỏi: Cho tổng: \({S_n} = \frac{1}{{1.5}} + \frac{1}{{5.9}} + \frac{1}{{9.13}} + ... + \frac{1}{{\left( {4n - 3} \right)\left( {4n + 1} \right)}}\). Tính \({S_3}\). 

A \({S_3} = \frac{1}{5}\)  

B \({S_3} = \frac{2}{9}\)

C \({S_3} = \frac{3}{{13}}\)

D \({S_3} = \frac{4}{{17}}\)