Hệ bất phương trình sau \(\left\{\begin{array}{l}...

B

- Hướng dẫn giải

Ta có

\(\left\{\begin{array}{l} 2 x-1 \geq 3(x-3) \\ \frac{2-x}{2}<x-3 \\ \sqrt{x-3} \geq 2 \end{array} \Leftrightarrow\left\{\begin{array}{l} 2 x-1 \geq 3 x-9 \\ 2-x<2 x-6 \\ x-3 \geq 4 \end{array} \Leftrightarrow\left\{\begin{array}{l} -x \geq-8 \\ -3 x<-8 \\ x \geq 7 \end{array} \Leftrightarrow\left\{\begin{array}{l} x \leq 8 \\ x>\frac{8}{3} \\ x \geq 7 \end{array} \Leftrightarrow 7 \leq x \leq 8\right.\right.\right.\right.\)