Theo mẫu nguyên tử Borh, khi electron trong nguyên...

B

- Hướng dẫn giải

Ta có: 

\(\begin{array}{l}
{F_d} = \frac{{K{e^2}}}{{{r^2}}} = {F_{ht}} = \frac{{m{v^2}}}{r} \to {E_d} = \frac{{m{v^2}}}{2} = \frac{{K{e^2}}}{{2r}}\\
{r_P} = 36{r_0} \to {E_{dP}} = \frac{{K{e^2}}}{{72{r_0}}}\\
{r_L} = 4{r_0} \to {E_{dL}} = \frac{{K{e^2}}}{{8{r_0}}}\\
\frac{{{E_{dL}}}}{{{E_{dP}}}} = \frac{{72}}{8} = 9
\end{array}\)