Hỗn hợp X gồm 2 amino axit no (chỉ có nhóm chức –C...

B

- Hướng dẫn giải

Amino axit no

\(\frac{m_{O}}{m_{N}}=\frac{80}{21}\, \, \, \, \, (1)\)\(\frac{m_{O}}{m_{N}}=\frac{80}{21}\, \, \, \, \, (1)\)

\(n_{H^{+}}=n_{N}\, (amino\, axit)\)

\(\Rightarrow n_{N}=0,03 (mol)\)

\(m_{N}=0,03.14=0,42(g)\)

\((1)\Rightarrow m_{O}=\frac{0,42.80}{21}=1,6(g)\)

\(n_{O}=0,1(mol)\)

\(X+O_{2}\rightarrow CO_{2}+H_{2}O+N_{2}\)

\(\left\{\begin{matrix} C: x(mol)\\H:y(mol) \end{matrix}\right.\Rightarrow 12x+y=3,83-1,6-0,42\)

\(12x+y=1,81\, \, \, \, \, (2)\)

\(C\rightarrow CO_{2}\)

x           x

\(2H\rightarrow H_{2}O\)

y              y/2

BT oxy:

\(\Rightarrow 0,1+2.\frac{3,192}{22,4}=2x+\frac{y}{2}\)

\((2),(3)\Rightarrow \left\{\begin{matrix} x=0,13\\y=0,25 \end{matrix}\right.\)

\(CO_{2}\rightarrow CaCO_{3}\downarrow\)

0,13.100 = 13(g)