Tìm giới hạn \(\mathop {\lim }\limits_{x \to 2} \d...

C

- Hướng dẫn giải

\(\begin{array}{l}\mathop {\lim }\limits_{x \to 2} \dfrac{{2{x^2} - 5x + 2}}{{{x^3} - 8}}\\ = \mathop {\lim }\limits_{x \to 2} \dfrac{{\left( {x - 2} \right)\left( {2x - 1} \right)}}{{\left( {x - 2} \right)\left( {{x^2} + 2x + 4} \right)}}\\ = \mathop {\lim }\limits_{x \to 2} \dfrac{{2x - 1}}{{{x^2} + 2x + 4}}\\ = \dfrac{{2.2 - 1}}{{{2^2} + 2.2 + 4}} = \dfrac{1}{4}\end{array}\)