Cho đường thẳng \(d:\dfrac{{x - 1}}{2} = \dfrac{{y...

A

- Hướng dẫn giải

\(d:\dfrac{{x - 1}}{2} = \dfrac{{y + 1}}{{ - 2}} = \dfrac{z}{3}\)

\(\Rightarrow \left\{ \begin{array}{l}x = 1 + 2t\\y =  - 1 - 2t\\z = 3t\end{array} \right.\)

\(\Rightarrow M\left( {1 + 2t; - 1 - 2t;3t} \right)\)

\(M = d \cap \left( P \right) \)

\(\Rightarrow 1 + 2t - 1 - 2t - 3t - 3 = 0\)

\(\Leftrightarrow  - 3t - 3 = 0 \)

\(\Leftrightarrow t =  - 1\)

\(\Rightarrow M\left( { - 1;1; - 3} \right)\)