Biết \(\int\limits_0^1 {x\ln \left( {{x^2} + 1} \r...

B

- Hướng dẫn giải

\(\begin{array}{l}I = \int\limits_0^1 {x\ln \left( {{x^2} + 1} \right){\rm{d}}x} \\t = {x^2} + 1 \Rightarrow dt = 2xdx\\ \Rightarrow I = \frac{1}{2}\int\limits_1^2 {\ln tdt} = \left. {\frac{1}{2}\left( {x\ln x - x} \right)} \right|_1^2 = \ln 2 - \frac{1}{2}\end{array}\)

\(P = 13a + 10b + 84c = 13 + 10 + 84.2 = 191\)