Khi tách nước từ một chất X...

B

- Hướng dẫn giải

$$\begin{gathered} {\mathrm{CH}}_3-\mathrm{CH}-{\mathrm{CH}}_2-\mathrm{OH} \underset{{170}^{\mathrm{o}}\mathrm{C}}{\overset{{\mathrm{H}}_2{\mathrm{SO}}_4 \mathrm{d}}{\to }}{\mathrm{CH}}_3-\mathrm{CH}-{\mathrm{CH}}_2-\mathrm{OH} \\ | | \\ {\mathrm{CH}}_3 {\mathrm{CH}}_3 \end{gathered}$$

${\mathrm{CH}}_3-\mathrm{CH}\left(\mathrm{OH}\right)-{\mathrm{CH}}_2-{\mathrm{CH}}_3 \underset{{170}^{\mathrm{o}}\mathrm{C}}{\overset{{\mathrm{H}}_2{\mathrm{SO}}_4 \mathrm{d}}{\to }}\left\{\begin{array}{l}{\mathrm{CH}}_2=\mathrm{CH}-{\mathrm{CH}}_2-{\mathrm{CH}}_3 + {\mathrm{H}}_2\mathrm{O}\\ {\mathrm{CH}}_3-\mathrm{CH}=\mathrm{CH}-{\mathrm{CH}}_3+ {\mathrm{H}}_2\mathrm{O}\end{array}\right.$

${\mathrm{CH}}_3-\left({\mathrm{CH}}_3\right)\mathrm{CH}\left(\mathrm{OH}\right)-{\mathrm{CH}}_3 \underset{{170}^{\mathrm{o}}\mathrm{C}}{\overset{{\mathrm{H}}_2{\mathrm{SO}}_4 \mathrm{d}}{\to }} {\mathrm{CH}}_3-\mathrm{C}\left({\mathrm{CH}}_3\right)={\mathrm{CH}}_2+ {\mathrm{H}}_2\mathrm{O}$

CH₃-O-CH₂-CH₂-CH₃ không tách nước

=> Chọn B