Nếu \({\log _7}x = 8{\log _7}a{b^2} - 2{\log _7}{a...

Câu hỏi: Nếu \({\log _7}x = 8{\log _7}a{b^2} - 2{\log _7}{a^3}b\) \(\left( {a,b > 0} \right)\) thì \(x\) bằng

A. \({a^4}{b^6}\)

B. \({a^2}{b^{14}}\)

C. \({a^6}{b^{12}}\)

D. \({a^8}{b^{14}}\)