Từ m gam 1minoaxxit X (có một nhóm –NH2...

B

- Hướng dẫn giải

\(\begin{array}{l}
\left\{ {\begin{array}{*{20}{c}}
{\mathop {2{C_x}{H_{2x + 1}}N{O_2}}\limits_a  \to Y:{\rm{ }}\mathop {{{\rm{C}}_{2x}}{H_{4x}}{N_2}{O_3}}\limits_{0,5a}  \to \mathop {2x{H_2}O}\limits_{ax} }\\
{\mathop {4{C_x}{H_{2x + 1}}N{O_2} \to Z}\limits_a :{\rm{ }}\mathop {{C_{4x}}{H_{8x - 2}}{N_4}{O_5}}\limits_{0,25a}  \to \mathop {\left( {4x - 1} \right){H_2}O}\limits_{0,25a(4x - 1)} }
\end{array}} \right.\\
 \Rightarrow \left\{ {\begin{array}{*{20}{c}}
{ax{\rm{ }} = {\rm{ }}0,18}\\
{0,25a\left( {4x{\rm{ }}--{\rm{ }}1} \right){\rm{ }} = {\rm{ }}0,165}
\end{array} \Rightarrow \left\{ {\begin{array}{*{20}{c}}
{a{\rm{ }} = {\rm{ }}0,06}\\
{x{\rm{ }} = {\rm{ }}3}
\end{array}} \right.} \right. \Rightarrow m{\rm{ }} = {\rm{ }}a\left( {14x{\rm{ }} + {\rm{ }}47} \right){\rm{ }} = {\rm{ }}5,34{\rm{ }}gam
\end{array}\)