Rút gọn:\(P = {{\left( {x + 1} \right)\left( {4{x^...

Câu hỏi: Rút gọn:\(P = {{\left( {x + 1} \right)\left( {4{x^2} - 4x + 1} \right) + \left( {x - 1} \right)\left( {4{x^2} - 4x + 1} \right)} \over {\left( {x + 3} \right)\left( {x - 1} \right) - {x^2} - 1}}\)       (với  \(\left( {2x - 1} \right) \ne 0\) )

A \(P = {{x{{\left( {2x - 1} \right)}^3}} \over {x - 2}}\)

B \(P = {{x{{\left( {2x - 1} \right)}^2}} \over {x - 2}}\)

C \(P = {{x{{\left( {x - 1} \right)}^2}} \over {x - 3}}\)

D \(P = {{x{{\left( {2x - 1} \right)}^2}} \over {2x - 2}}\)