Đun 0,4 mol ancol X no, đơn chức với H2...

B

- Hướng dẫn giải

Phương pháp giải:

\(\begin{gathered}
X:{C_n}{H_{2n + 1}}OH \hfill \\
{C_n}{H_{2n + 1}}OH\xrightarrow{{{H_2}S{O_{4d}},{{170}^o}C}}{C_n}{H_{2n}} + {\text{ }}{H_2}O \hfill \\
{C_n}{H_{2n}} + {\text{ }}B{r_2} \to {C_n}{H_{2n}}B{r_2} \hfill \\
= > {\text{ }}{n_{brom}} = {\text{ }}{n_{anken}} = {\text{ }}{n_{ancol}} \hfill \\
\end{gathered} \)

Giải chi tiết:

\(\begin{gathered}
X:{C_n}{H_{2n + 1}}OH \hfill \\
{C_n}{H_{2n + 1}}OH\xrightarrow{{{H_2}S{O_{4d}},{{170}^o}C}}{C_n}{H_{2n}} + {\text{ }}{H_2}O \hfill \\
0,4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,4 \hfill \\
{C_n}{H_{2n}} + {\text{ }}B{r_2} \to {C_n}{H_{2n}}B{r_2} \hfill \\
0,4\,\,\,\,\,\,\,\,\,\,\,\,\,0,4 \hfill \\
= > {\text{ }}{m_{B{r_2}}} = 0,4.160 = 64gam \hfill \\
\end{gathered} \)

Đáp án B