- Hướng dẫn giải

$\begin{array}{l}\underset{x\to 0}{\lim }\frac{\sin 2x}{\tan 3x}=\underset{x\to 0}{\lim }\frac{\sin 2x.c\text{os 3x}}{\sin 3x}\\ =\underset{x\to 0}{\lim }\frac{2.\frac{\sin 2x}{2x}.c\text{os3x}}{3.\frac{\sin 3x}{3x}}=\frac{\mathrm{2.1.}c\text{os0}}{3.1}=\frac{2}{3}\end{array}$

ĐÁP ÁN C