Dẫn V lít (đktc) hỗn hợp X gồm axetilen và hidro đ...

A

- Hướng dẫn giải

Phương pháp giải:

Giải chi tiết:

\(\begin{gathered}
{n_ \downarrow } = {n_{A{g_2}{C_2}}} = \frac{{12}}{{240}} = 0,05(mol) \hfill \\
X\left\{ \begin{gathered}
{C_2}{H_2} \hfill \\
{H_2} \hfill \\
\end{gathered} \right.\xrightarrow{{Ni,to}}Y\left\{ \begin{gathered}
{C_2}{H_{2\,du}}:a \hfill \\
{C_2}{H_4}:b \hfill \\
{C_2}{H_6} \hfill \\
{H_{2\,du}} \hfill \\
\end{gathered} \right.\xrightarrow{{ + AgN{O_3}/N{H_3}du}}\left\{ \begin{gathered}
A{g_2}{C_2}:0,05 \hfill \\
hh\,khi\left\{ \begin{gathered}
{C_2}{H_4}:b \hfill \\
{C_2}{H_6} \hfill \\
{H_{2\,}}du \hfill \\
\end{gathered} \right\}\xrightarrow{{ + B{r_2}:0,1}}Z\left\{ \begin{gathered}
{C_2}{H_6} \hfill \\
{H_2} \hfill \\
\end{gathered} \right.\xrightarrow{{ + O2du}}\left\{ \begin{gathered}
C{O_2}:0,1 \hfill \\
{H_2}O:0,25 \hfill \\
\end{gathered} \right. \hfill \\
\end{gathered} \right. \hfill \\
*a = {n_{A{g_2}{C_2}}} = 0,05(mol) \hfill \\
*b = {n_{B{r_2}}} = 0,1(mol) \hfill \\
\xrightarrow{{BTC}}2{n_{{C_2}{H_2}}} = 2{n_{{C_2}{H_{2\,du}}}} + 2{n_{{C_2}{H_4}}} + {n_{C{O_2}}} \to {n_{{C_2}{H_2}}} = \frac{{2.0,05 + 2.0,1 + 0,1}}{2} = 0,2(mol) \hfill \\
\xrightarrow{{BTH}}2{n_{{C_2}{H_2}}} + 2{n_{{H_2}}} = 2{n_{{C_2}{H_{2\,du}}}} + 4{n_{{C_2}{H_4}}} + 2{n_{{H_2}O}} \to 2.0,2 + 2nH2 = 2.0,05 + 4.0,1 + 2.0,25 \hfill \\
\to {n_{{H_2}}} = 0,3(mol) \hfill \\
\Rightarrow V = 22,4(0,2 + 0,3) = 11,2(l) \hfill \\
\end{gathered} \)

Đáp án A