Hiđrat hóa 5,2 gam axetilen với xúc tác HgSO4...

A

- Hướng dẫn giải

Phương pháp giải:

\(\begin{gathered}
{n_{{C_2}{H_2}}} = \frac{{5,2}}{{26}} = 0,2\,(mol)\, \hfill \\
{C_2}{H_2}\xrightarrow{{ + {H_2}O(xt\,H{g^{2 + }})}}\left\{ \begin{gathered}
C{H_3}CHO:a \hfill \\
{C_2}{H_2}\,du:b \hfill \\
\end{gathered} \right.\xrightarrow{{ + AgNO3}}\left\{ \begin{gathered}
Ag:2a\,(mol) \hfill \\
A{g_2}{C_2}:b(mol) \hfill \\
\end{gathered} \right. \hfill \\
\left\{ \begin{gathered}
\sum {{n_{{C_2}{H_2}}} = a + b = 0,2} \hfill \\
\sum\limits_{} {m \downarrow = 108.2a + 240b = 44,16} \hfill \\
\end{gathered} \right. = > \left\{ \begin{gathered}
a = ? \hfill \\
b = ? \hfill \\
\end{gathered} \right. \hfill \\
\% H = \frac{{{n_{{C_2}{H_2}pu}}}}{{{n_{{C_2}{H_2}bd}}}}.100\% = ? \hfill \\
\end{gathered} \)

Giải chi tiết:

\(\begin{gathered}
{n_{{C_2}{H_2}}} = \frac{{5,2}}{{26}} = 0,2\,(mol)\, \hfill \\
{C_2}{H_2}\xrightarrow{{ + {H_2}O(xt\,H{g^{2 + }})}}\left\{ \begin{gathered}
C{H_3}CHO:a \hfill \\
{C_2}{H_2}\,du:b \hfill \\
\end{gathered} \right.\xrightarrow{{ + AgNO3}}\left\{ \begin{gathered}
Ag:2a\,(mol) \hfill \\
A{g_2}{C_2}:b(mol) \hfill \\
\end{gathered} \right. \hfill \\
\left\{ \begin{gathered}
\sum {{n_{{C_2}{H_2}}} = a + b = 0,2} \hfill \\
\sum\limits_{} {m \downarrow = 108.2a + 240b = 44,16} \hfill \\
\end{gathered} \right. = > \left\{ \begin{gathered}
a = 0,16 = {n_{{C_2}{H_2}pu}} \hfill \\
b = 0,04 \hfill \\
\end{gathered} \right. \hfill \\
\% H = \frac{{{n_{{C_2}{H_2}pu}}}}{{{n_{{C_2}{H_2}bd}}}}.100\% = \frac{{0,16}}{{0,2}}.100\% = 80\% \hfill \\
\end{gathered} \)

Đáp án A