Viết công thức phân tử của A...

- Hướng dẫn giải

$$\begin{gathered} \stackrel{{\mathrm{M}}_{\mathrm{E}}=58\mathrm{\%}\mathrm{C}=62\mathrm{\%}}{\to }\mathrm{E}:{\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O} \mathrm{va} \mathrm{A} \\ \stackrel{\mathrm{men}}{\to }\left\{\begin{array}{l}{\mathrm{CO}}_2\\ \mathrm{B}\to \mathrm{B}:{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}\end{array}\right. \end{gathered}$$

$$\begin{gathered} {\mathrm{C}}_6{\mathrm{H}}_{12}{\mathrm{O}}_6\stackrel{\mathrm{men}}{\to }2{\mathrm{CO}}_2+2{\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH} \\ {\mathrm{C}}_2{\mathrm{H}}_5\mathrm{OH}+2{\mathrm{H}}_2{\mathrm{CrO}}_4\to {\mathrm{CH}}_3\mathrm{COOH}+2{\mathrm{H}}_2{\mathrm{CrO}}_3 \\ +{\mathrm{H}}_2\mathrm{O} \\ 2{\mathrm{CH}}_3\mathrm{COOH}+\mathrm{Ca}(\mathrm{OH}{)}_2\to ({\mathrm{CH}}_3\mathrm{COO}{)}_2\mathrm{Ca}+2{\mathrm{H}}_2\mathrm{O} \\ ({\mathrm{CH}}_3\mathrm{COO}{)}_2\mathrm{Ca}\stackrel{{\mathrm{t}}^{\mathrm{o}}}{\to }{\mathrm{CaCO}}_3+{\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O} \\ 3{\mathrm{C}}_3{\mathrm{H}}_6\mathrm{O}\stackrel{{\mathrm{H}}_2{\mathrm{SO}}_4}{\to }{\mathrm{C}}_9{\mathrm{H}}_{12}+3{\mathrm{H}}_2\mathrm{O} \end{gathered}$$