Trong các amino axit dưới đây: Gly, Ala, Glu, Lys,...

A

- Hướng dẫn giải

Phương pháp giải:

Giải chi tiết:

Hướng dẫn giải

\(\eqalign{ & {H_2}N - \mathop {\mathop {CH}\limits_| }\limits_{C{H_3}} - C{\rm{OO}}H\,\,\,\,\,\,\,\,\,Ala = > 1( - COOH)\,\,,\,\,\,1( - N{H_2}) \cr & N{H_2} - {\left( {C{H_2}} \right)_4} - CH\left( {N{H_2}} \right) - COOH\,\,\,Ly{\mathop{\rm s}\nolimits} = > 1( - COOH)\,\,,\,\,\,2( - N{H_2}) \cr & {C_6}{H_5} - C{H_2} - \mathop {\mathop {CH}\limits_| }\limits_{N{H_2}} - C{\rm{OO}}H\,\,\,\,\,\,\,\,\,\,\,\,\,phe = > 1( - COOH)\,\,,\,\,\,1( - N{H_2}) \cr & {(C{H_3})_2}CH - \mathop {\mathop {CH}\limits_| }\limits_{N{H_2}} - CO\,OH\,\,\,\,\,Val = > 1( - COOH)\,\,,\,\,\,1( - N{H_2}) \cr} \)

\(\eqalign{ & {H_2}N - C{H_2} - C{\rm{OO}}H\,\,\,\,Gly = > 1( - COOH)\,\,,\,\,\,1( - N{H_2}) \cr & HOOC - {(C{H_2})_2} - CH(N{H_2}) - COOH\,\,\,\,\,\,Glu\,\,\,\,\, = > 2( - COOH)\,\,,\,\,\,1( - N{H_2}) \cr & C{H_3} - CH(C{H_3}) - C{H_2} - CH(N{H_2}) - COOH\,\,\,\,Leu = > 1( - COOH)\,\,,\,\,\,1( - N{H_2}) \cr & HO - C{}_6{H_4} - C{H_2} - CH(N{H_2}) - COOH\,\,\,\,\,\,T{\rm{yr}} = > 1( - COOH),\,\,1( - N{H_2}) \cr} \)

Số amino axit có số nhóm amino bằng số nhóm cacboxyl là Ala,Phe, Val, Gly, Leu,Tyr,

Chọn A

* Leu (Leuxin):  axit 2-amino-4-metylpentanoic

 \(C{H_3} - \mathop {\mathop {CH}\limits_| }\limits_{C{H_3}}  - C{H_2} - \mathop {\mathop {CH}\limits_| }\limits_{N{H_2}}  - CO{\rm{OH}}\)