Cho 13,44 lít (đktc) hỗn hợp X gồm C2H

C

- Hướng dẫn giải

\({M_{{C_2}{H_{}}}} = 24 + \overline y = 14,4.2 \to \overline y = 4,8 \to Y:\,\,{C_2}{H_{4,8}}\,\,(1,4\pi )\)

\({C_2}{H_2} + 1,4{H_2}\xrightarrow{{}}{C_2}{H_{4,8}}\)

a            1,4a

\(\to {n_X} = a + 1,4a = 0,6 \to a = 0,25\,\,mol\)

\(\xrightarrow{{BT\,\,mol\,\,\pi }}2{n_{{C_2}{H_2}}} = {n_{{H_2}}} + {n_{B{r_2}}} \to 2.0,25 = 1,4.0,25 + {n_{B{r_2}}} \to {n_{B{r_2}}} = 0,15\,\,mol\)