Từ đá vôi, than đá, các chất vô cơ cần thiết khác...

- Hướng dẫn giải

Phương pháp giải:

Giải chi tiết:

\(\eqalign{
& CaC{O_3} + {\rm{ }}4C\buildrel {{t^o}} \over
\longrightarrow Ca{C_2} + {\rm{ }}3CO \cr
& Ca{C_2} + {\rm{ }}2{H_2}O{\rm{ }} \to {\rm{ }}Ca{\left( {OH} \right)_2} + {\rm{ }}CH \equiv CH \cr
& CH \equiv CH{\rm{ }} + {\rm{ }}HCl\buildrel {xt,{t^o}} \over
\longrightarrow C{H_2} = CHCl \cr
& nC{H_2} = CHCl\buildrel {Trung\,hop} \over
\longrightarrow - {[CH2 - CH\left( {Cl} \right)]_n} - {\rm{ }}\left( {PVC:{\rm{ }}polivinylclorua} \right) \cr
& CH \equiv CH{\rm{ }} + {\rm{ }}{H_2}O\buildrel {HgS{O_4}{{,80}^o}} \over
\longrightarrow C{H_3}CHO \cr
& C{H_3}CHO{\rm{ }} + {\rm{ }}{H_2}\buildrel {Ni,\,{t^o}} \over
\longrightarrow {C_2}{H_5}OH \cr
& C{H_3}CHO{\rm{ }} + {\rm{ }}1/2{O_2}\buildrel {{t^o}} \over
\longrightarrow C{H_3}COOH \cr
& C{H_3}COOH{\rm{ }} + {\rm{ }}{C_2}{H_5}OH\buildrel {{H_2}S{O_4}} \over
\longrightarrow C{H_3}COO{C_2}{H_5} + {\rm{ }}{H_2}O \cr
& C{H_3}COOH{\rm{ }} + {\rm{ }}NaOH{\rm{ }} \to {\rm{ }}C{H_3}COONa{\rm{ }} + {\rm{ }}{H_2}O \cr
& C{H_3}COONa{\rm{ }} + {\rm{ }}NaOH\buildrel {CaO,{t^o}} \over
\longrightarrow C{H_4} + {\rm{ }}N{a_2}C{O_3} \cr
& C{H_4} + {\rm{ }}C{l_2}\buildrel {{\rm{as}}} \over
\longrightarrow C{H_3}Cl{\rm{ }} + {\rm{ }}HCl \cr} \)