Cho 

Câu hỏi: Cho $\frac{{\text{4x}}^{\text{2}}+\text{3x}-\text{7}}{\text{A}}=\frac{\text{4x}+\text{7}}{\text{x}+\text{3}}(x\ne -3;x\ne \frac{-\text{7}}{\text{4}})$  Khi đó đa thức A là?

A. $A = x^2 + 2x - 3$

B. $A = x^2 + 2x + 3$

C. $A = x^2 - 2x - 3$

D. $A = x^2 + 2x$