\(M=C_{15}^{0}+6C_{15}^{1}+{{6}^{2}}C_{15}...

Câu hỏi: \(M=C_{15}^{0}+6C_{15}^{1}+{{6}^{2}}C_{15}^{2}+...+{{6}^{15}}C_{15}^{15}.\) Khi đó M bằng: 

A  \({{5}^{15}}\)                                    

B  \({{6}^{15}}\)                                    

C \({{7}^{15}}\)                                     

 

D \(-{{5}^{15}}\)