Một lít dung dịch nước cứng tạm thời có thể làm mề...

B

- Hướng dẫn giải

Phương pháp giải:

Giải chi tiết:

\(\begin{gathered}
Ca{(HC{O_3})_2} + Ca{(OH)_2} \to 2CaC{O_3} + 2{H_2}O \hfill \\
x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,2x \hfill \\
Mg{(HC{O_3})_2} + Ca{(OH)_2} \to MgC{O_3} + CaC{O_3} + 2{H_2}O \hfill \\
y\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,y \hfill \\
\to \left\{ \begin{gathered}
x + y = {n_{Ca{{(OH)}_2}}} = 0,001 \hfill \\
100(2x + y) + 84.y = {m_ \downarrow } = 0,192 \hfill \\
\end{gathered} \right. \to \left\{ \begin{gathered}
x = {5.10^{ - 4}} \hfill \\
y = {5.10^{ - 4}} \hfill \\
\end{gathered} \right. \hfill \\
\end{gathered} \)

Đáp án B